Verify the identity sin (A - B) / sin (A + B) = (a^2 - b^2)/c^2.
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Originally Posted by pacman Verify the identity sin (A - B) / sin (A + B) = (a^2 - b^2)/c^2. Does this identity refer to a triangle with sides of length a, b and c and angles A, B and C opposite those sides?
Yes, it refers to a triangle. . . . i use cosine law but can not arrived to the identity. . . .
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