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- Sep 26th 2009, 02:05 PM #1

- Joined
- Nov 2008
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- Sep 26th 2009, 02:11 PM #2

- Sep 26th 2009, 10:40 PM #3
sin(6x)/sin(2x) = sin(3x)

(2sin 3x cos 3x)/sin 2x = sin 3x,

that red thing (sin 2x) SHOULD be cos 3x, and 2 should be introduced to the RHS, to generate an identity. . . . see below

(2sin 3x cos 3x)/cos 3x = 2 sin 3x