my question is what is the period of f(x)= cot(119x)+sec(112x)? I do not understand what to do. I know that cotangent is pi/2 and secant is 2pi/2, but cant get the right answer
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Solution: Given f(x)= cot(119x)+sec(112x) we can write it as cot(119(x+π/7))+sec (112(x+π/7)) there for the period is π/7
October 2005 ... u were just a little late