Could someone simplify these plz

A)5cosx>>*sin^2x - sinxcosx

sin^2x >> * sin^2x cos^2x

B) (tanx + 2)(tanx - 3) - (6 - tanx) + 2 tanx

C)cot- 1

secx - tanx

x = theta

Printable View

- Jan 21st 2007, 06:36 AMmortyrSimplify
Could someone simplify these plz

A)__5cosx__>>*__sin^2x - sinxcosx__

sin^2x >> * sin^2x cos^2x

B) (tanx + 2)(tanx - 3) - (6 - tanx) + 2 tanx

C)__cot__- 1

secx - tanx

x = theta - Jan 21st 2007, 07:05 AMturtle
B) (tanx + 2)(tanx - 3) - (6 - tanx) + 2 tanx

I believe you first need to open up the parentheses, so:

(tanx)^2 - 3tanx + 2tanx -6

combine all the like terms, and you should get:

(tanx)^2 + 2tanx - 12 - Jan 21st 2007, 07:16 AMSoroban
Hello, mortyr!

The first two are just "algebra": multiplying, cancelling, and combining.

Quote:

We have: .

Multiply top and bottom by

and we have: .

Reduce: .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Here's another approach . . .

. . guarenteed to impress/surprise/terrify your teacher.

Multiply top and bottom of the fraction by

. .

Since , we have: .

Then we have: .

Since , we have: .

And we have: .