Prove that the equation is an identity cosθ(secθ-cosθ)=sin^2 θ
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Hello blame_canada100 Originally Posted by blame_canada100 Prove that the equation is an identity cosθ(secθ-cosθ)=sin^2 θ Two things you need to know here: $\displaystyle \sec\theta = \frac{1}{\cos\theta}$ $\displaystyle \sin^2\theta = 1-\cos^2\theta$ Grandad
cosθ(secθ-cosθ)=sin^2 θ, the left hand side of the equation seems tempting, cos θ (1/cos θ - cos θ) = cos θ (1/cos θ) - cos θ cos θ = 1 - cos^2 θ = ?
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