sin(3x) = cos(x + pi/4)

Thanks

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- Sep 16th 2009, 02:14 AMusagi_killerSolve this trig equation
sin(3x) = cos(x + pi/4)

Thanks - Sep 16th 2009, 02:23 AMramiee2010
my attempt

sin 3x = cos(x+pi/4)

sin 3x= sin{ pi/2- (x+pi/2)}

sin 3x= sin( pi/4 - x )

gives

3x=pi/4 - x

x=pi/16 - Sep 16th 2009, 02:44 AMsimplependulum

Or

- Sep 16th 2009, 03:02 AMusagi_killer
where did 2 n come from?

- Sep 16th 2009, 04:28 AMmathaddict
- Sep 18th 2009, 03:35 AMpacman
i have plotted this function, sin(3x) - cos(x + pi/4) = 0, for x = 0 to 2pi

it does have 6 roots for x = 0 to 2 pi

using the sum to product formula, we have this

-2 sin (pi/8 -2x) cos (x + pi/8) = 0

this one form does not generate the 6 roots as shown in the plot, i wonder