Okay I can't seem to think of how to solve this
I basically need to have the y force be zero... currently I have
90 + 70 sin(x) - 130 cos(x) = 0
I feel like there is an inverse tan in my future but I can't get there...
Hello msuMath311This question doesn't make much sense. Do you need to solve this equation for $\displaystyle x$? If so, do this:
$\displaystyle 130\cos x - 70\sin x = 90$
Let $\displaystyle 130\cos x - 70 \sin x = R\cos(x + \alpha) = R\cos x\cos\alpha-R\sin x\sin\alpha$
$\displaystyle \Rightarrow R^2 = 130^2 + 70^2$ and $\displaystyle \tan\alpha = \frac{70}{130}$
Can you complete it from here?
Grandad