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Math Help - Prove this

  1. #1
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    Prove this

    Prove this guys,.,thanks



    2 csc θ = 1 - cos θ + sin θ
    --------- --------
    sin θ 1-cos θ
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  2. #2
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    is that supposed to be :

    \frac{2csc\theta}{sin\theta}=\frac{1-cos\theta+sin\theta}{1-cos\theta} ?
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by seld View Post
    is that supposed to be :

    \frac{2csc\theta}{sin\theta}=\frac{1-cos\theta+sin\theta}{1-cos\theta} ?
    But that is not an identity.

    Looking at the source it appears that:

    2\csc (\theta)= 1 -\frac{\cos(\theta)}{\sin(\theta)} +\frac{\sin(\theta)}{1-\cos(\theta)}

    is the indended expression, but that is also not an identity.

    CB
    Last edited by CaptainBlack; September 15th 2009 at 02:40 AM. Reason: put back the 2 that got lost
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  4. #4
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    Quote Originally Posted by CaptainBlack View Post
    But that is not an identity.

    CB

    true, but that's all I could make of the original post with the


    ----- -------
    sin x 1-cosx


    doesn't make any sense to me to have (sin x)*1-cos x as a denominator.



    looking at the source? err . . . the 2 dissapeared . . .
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  5. #5
    Grand Panjandrum
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    Quote Originally Posted by seld View Post
    true, but that's all I could make of the original post with the


    ----- -------
    sin x 1-cosx


    doesn't make any sense to me to have (sin x)*1-cos x as a denominator.



    looking at the source? err . . . the 2 dissapeared . . .
    If you had quoted what the OP had posted you will have seen what they typed, and been better able to interpret it.

    I have put the lost 2 back where it belongs now.

    CB
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