Sin2x=1/2 x = pi/12, 11pi/12 That is all i have come up with but i think there are two other values for x
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Originally Posted by Raj Sin2x=1/2 x = pi/12, 11pi/12 That is all i have come up with but i think there are two other values for x There are two more -- add $\displaystyle \pi$ to the solutions you have to generate the others.
Originally Posted by Chris L T521 There are two more -- add $\displaystyle \pi$ to the solutions you have to generate the others. why is it that i don't add 2$\displaystyle \pi$ to the solutions, i mean why do I add $\displaystyle \pi$
Originally Posted by Raj why is it that i don't add 2$\displaystyle \pi$ to the solutions, i mean why do I add $\displaystyle \pi$ Its "technically" $\displaystyle 2\pi$, but you had already divided your answers by 2 - hence the reason you add $\displaystyle \pi$ instead.
Ah thanks. I guess finding the solutions and dividing last works
see the graph, it crosses the x-axis 4 times, x is in radians. But would it be values in the first quadrant and the second quadrant be the valid answer? Since it is positive, just as noted above? x = pi/12, 11pi/12. Period is pi.
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