Find the value of x in fourth quadrant if $\displaystyle Tan x=-\sqrt{3}$
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In the 4th quadrant consider $\displaystyle 2\pi-\theta$ Where $\displaystyle \theta = \frac{\pi}{3}$ is an angle on the triangle with $\displaystyle \tan(\theta) = \frac{O}{A} = \frac{\sqrt{3}}{1}$ $\displaystyle 2\pi-\frac{\pi}{3}= \dots$
The value of x is -60 when I used the calculator.After that I am lost cause tan is negative in fourth quadrant.
Originally Posted by roshanhero Find the value of x in fourth quadrant if $\displaystyle Tan x=-\sqrt{3}$ The reference angle is 60 degree . So in the 4th quadrant : 360 -60 = 300 degree in fact , tan 300 = tan (-60) because tan(-60)=-(tan 60) = -(-tan 300)=tan 300
Originally Posted by roshanhero The value of x is -60 when I used the calculator.After that I am lost cause tan is negative in fourth quadrant. both -60 and 360-60 = 300 are the same angle and in the 4th quadrant. -60 is going clockwise and 300 counter clockwise, you end up at the same point.
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