# Find the slope-intercept form of the line passing through the point (7, -2) and paral

• Sep 6th 2009, 09:06 AM
Robby
Find the slope-intercept form of the line passing through the point (7, -2) and paral
Find the slope-intercept form of the line passing through the point (7, -2) and parallel to the line y=-8x-4?
• Sep 6th 2009, 09:23 AM
ANDS!
\$\displaystyle y-y_{1}=m(x-x_{1})\$ is the point-slope form of a line. I mention this one first because we are given a point on a line and told to find it's equation. All we lack is a slope.

We are told though, that this particular line is PARALLEL to the line defined as \$\displaystyle y=-8x-4\$. To be parallel means that our two lines have the same slope correct? Knowing that, we have the slope of \$\displaystyle y=-8x-4\$ as \$\displaystyle -8\$ and we can then plug that back into our point-slope form of a line.

All that is left to do at this point (no pun intended) is to put it into slope-intercept form.
• Sep 6th 2009, 09:24 AM
galactus
Since the line is parallel to y=-8x-4, it has the same slope.

Now, since we have the slope m, and a point it passes through, we can solve for the y-intercept, b, and that's it.

\$\displaystyle -2=-8(7)+b\$

Solve for b and then set up the slope intercept form, y=mx+b