Results 1 to 2 of 2

Math Help - Easy trig simplification problem.

  1. #1
    Newbie
    Joined
    Sep 2009
    Posts
    4

    Easy trig simplification problem.

    I know this problem is very easy, I am just having so much trouble grasping the concept. I have to verify this problem and don't know where to start.
    Any help GREATLY appreciated. Homework due at 3PM today.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Aug 2009
    From
    Gothenburg, Sweden
    Posts
    37
    We know that \sec t=\frac{1}{\cos t}, \csc t=\frac{1}{\sin t} and \cos^2 t + \sin^2 t =1 so starting with the LHS:
    LHS =\frac{\sec t}{\cos t}-\frac{\sec^2 t}{\csc^2 t}=\frac{\frac{1}{\cos t}}{\cos t}-\frac{\frac{1}{\cos^2 t}}{\frac{1}{\sin^2 t}}=\frac{1}{\cos^2 t}-\frac{\sin^2 t}{\cos^2 t} =\frac{1-\sin^2 t}{\cos^2 t}=\frac{\cos^2 t}{\cos^2 t}=1=RHS
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. another easy trig problem...
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: February 17th 2011, 08:53 PM
  2. Another easy trig. problem...
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: February 17th 2011, 07:29 PM
  3. Logarithm simplification (probably easy)
    Posted in the Calculus Forum
    Replies: 6
    Last Post: January 21st 2011, 12:08 PM
  4. Easy trig problem
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: July 2nd 2010, 11:04 PM
  5. Easy simplification of a function
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: October 15th 2009, 05:50 PM

Search Tags


/mathhelpforum @mathhelpforum