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Thread: Easy trig simplification problem.

  1. September 4th 2009, 09:21 AM #1
    kdickson91
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    Easy trig simplification problem.

    I know this problem is very easy, I am just having so much trouble grasping the concept. I have to verify this problem and don't know where to start.
    Any help GREATLY appreciated. Homework due at 3PM today.
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  2. September 4th 2009, 02:15 PM #2
    DavidEriksson
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    We know that \sec t=\frac{1}{\cos t}, \csc t=\frac{1}{\sin t} and \cos^2 t + \sin^2 t =1 so starting with the LHS:
    LHS =\frac{\sec t}{\cos t}-\frac{\sec^2 t}{\csc^2 t}=\frac{\frac{1}{\cos t}}{\cos t}-\frac{\frac{1}{\cos^2 t}}{\frac{1}{\sin^2 t}}=\frac{1}{\cos^2 t}-\frac{\sin^2 t}{\cos^2 t} =\frac{1-\sin^2 t}{\cos^2 t}=\frac{\cos^2 t}{\cos^2 t}=1=RHS
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