Hi, I have a problem which I am having trouble solving.

Let $\displaystyle ABC$ be a right-angled triangle. A circle $\displaystyle T$ having side $\displaystyle AC$ as its diameter meets hypotenuse $\displaystyle AB$ at point $\displaystyle E$. A tangent line to $\displaystyle T$ at point $\displaystyle E$ meets side $\displaystyle BC$ at point $\displaystyle D$. Prove that triangle $\displaystyle BDE$ is isosceles.

Please help, BG