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**Robb** A stack of cards contains four Aces, three Kings, two Queens and six other cards. Seven cards are randomly drawn from the stack, without replacement.

(a) Find the probability that the drawn cards contain at least one Ace.

no problem.. $\displaystyle Pr = 1 - Pr(0 \ aces) = 1- \frac{ \left(\begin{array}{cc}4\\0\end{array}\right) \left(\begin{array}{cc}11\\7\end{array}\right)}{\l eft(\begin{array}{cc}15\\7\end{array}\right)}=1-\frac{330}{6435}=0.9487 $

(b) Find the probability that the drawn cards contain exactly two Aces if it is known that they contain no Kings or Queens.

Now im not sure what it means by 'if it is known that they contain no Kings or queens. Should I just use

$\displaystyle \frac{ \left(\begin{array}{cc}4\\2\end{array}\right) \left(\begin{array}{cc}6\\5\end{array}\right)}{\le ft(\begin{array}{cc}15\\7\end{array}\right)}$

I am thinking this doesn't really make sense, since it is known that it doens't contain any kings or queens...