I am trying to figure out the number of possible combinations which I can arrange this sequence:
123456
where:
4 can also be X
5 can also be Y
6 can also be Z
For example, 1 combination can be:
12345Z
Is the proper equation combinations = (n^n) -1
where n is the number of variables that can be change?
For my example I think think the number of combinations would be 8
(3^3) -1
Thanks for any help!
Mr. EKO