1. ## dice

Throw outcome
1 lose 3.rs
2 lose 2.rs
3 lose 1.rs
4 neither
5 win 1.rs
6 win 5.rs

this table represents a outcome of a single dice when thrown ...now what is probability of having of having at least 5.rs at the end of 2 throws ..

my ans is 1/9 is it correct

2. I get five different pairs each gives at least 5rs.

3. Hello, arunachalam.s!

Edit: Once again, I've made a really stupid blunder . . . embarrassing!

A die is thrown. These are the payoffs.

. . . $\begin{array}{c|c}
\text{Throw} & \text{Payoff (\)} \\ \hline
1 & \text{-}3 \\ 2 & \text{-}2 \\ 3 & \text{-}1 \\ 4 & 0 \\ 5 & +1 \\ 6 & +5 \end{array}$

What is the probability of having of having at least $5 at the end of 2 throws? My answer is $\tfrac{1}{9}$ . Is it correct? . . . . no There are $6^2 = 36$ outcomes for two rolls of a die. To win at least$5, we must:

. . Roll a 4 and a 6 in some order: . $(4,6),(6,4)$ . . . two ways.

. . Roll a 5 and a 6 in some order: . $(5,6), (6,5)$ . . . two ways.

. . Roll a 6 and a 6: . ${\color{blue}(6,6)}$ . . . one way.

Hence, there are five ways to have at least \$5.

Therefore: . $P(\text{at least \5}) \:=\:{\color{blue}\frac{5}{36}}$