I get five different pairs each gives at least 5rs.
Have I missread the question?
Throw outcome
1 lose 3.rs
2 lose 2.rs
3 lose 1.rs
4 neither
5 win 1.rs
6 win 5.rs
this table represents a outcome of a single dice when thrown ...now what is probability of having of having at least 5.rs at the end of 2 throws ..
my ans is 1/9 is it correct
Hello, arunachalam.s!
Edit: Once again, I've made a really stupid blunder . . . embarrassing!
There are outcomes for two rolls of a die.A die is thrown. These are the payoffs.
. . .
What is the probability of having of having at least $5 at the end of 2 throws?
My answer is . Is it correct? . . . . no
To win at least $5, we must:
. . Roll a 4 and a 6 in some order: . . . . two ways.
. . Roll a 5 and a 6 in some order: . . . . two ways.
. . Roll a 6 and a 6: . . . . one way.
Hence, there are five ways to have at least $5.
Therefore: .