# Math Help - venn diagram problem little confusion

1. ## venn diagram problem little confusion

.In a survey of voting in a election, if 55% of the voters who casted their votes supported person ‘x’ , 61% supported ‘y’ and 80% supported both of them, then what percentage of people supported neither ‘x’ nor ‘y’?

2. Originally Posted by bluffmaster.roy.007
.In a survey of voting in a election, if 55% of the voters who casted their votes supported person ‘x’ , 61% supported ‘y’ and 80% supported both of them, then what percentage of people supported neither ‘x’ nor ‘y’?
Calculate $\Pr(A \cup B) = \Pr(A) + \Pr(B) - \Pr(A \cap B)$. Then the answer is $1 - \Pr(A \cup B)$. Multiply by 100 to convert into a percentage.

3. Is there a mistake in the question or do i not understand?
How can the number who support both (80%) be larger than those
who supported x (55%) and y (61%).
Because the number who supports both should be an intersection of x and y