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Math Help - Probability at its easiest!

  1. #1
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    Probability at its easiest!

    Problem: Monster drops item 1/10 of the time. I can only have 4 monster at a time per trial/save. So if I have 4 monsters that drop 1/10 of the time... my chance of getting at least 1 item is 40% a try instead of with just 1 monster a try at 10%?
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  2. #2
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    Quote Originally Posted by UnknownEntity View Post
    Problem: Monster drops item 1/10 of the time. I can only have 4 monster at a time per trial/save. So if I have 4 monsters that drop 1/10 of the time... my chance of getting at least 1 item is 40% a try instead of with just 1 monster a try at 10%?
    No. Calculate the probability of no drops and subtract that number from 1.

    Alternatively:

    X is the random variable number of drops.
    X ~ Binomial(n = 4, p = 1/10)
    \Pr (X \geq 1) = 1 - \Pr(X = 0) = 1 - \left( \frac{9}{10}\right)^4.
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  3. #3
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    Quote Originally Posted by mr fantastic View Post
    No. Calculate the probability of no drops and subtract that number from 1.

    Alternatively:

    X is the random variable number of drops.
    X ~ Binomial(n = 4, p = 1/10)
    \Pr (X \geq 1) = 1 - \Pr(X = 0) = 1 - \left( \frac{9}{10}\right)^4.
    Ahhh, so my Probability of getting 1 item would be somewhere around 34%, not 40%. Thanks for the help!
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