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Math Help - elevator's problem ( almost solved)

  1. #1
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    elevator's problem ( almost solved)

    I just need help with the last question because I'm not sure how to do it!!!

    The population of weights for men attending a local health club is normally distributed with a mean of 176-lbs and a standard deviation of 29-lbs. An elevator in the health club is limited to 32 occupants, but it will be overloaded if the total weight is in excess of 5984-lbs.
    Assume that there are 32 men in the elevator. What is the average weight beyond which the elevator would be considered overloaded?
    average weight = 187 lbs
    What is the probability that one randomly selected male health club member will exceed this weight?
    P(one man exceeds) = .3522
    If we assume that 32 male occupants in the elevator are the result of a random selection, find the probability that the elevator will be overloaded?
    P(elevator overloaded) = .0159
    If the evelator is full (on average) 8 times a day, how many times will the evelator be overloaded in one (non-leap) year?
    number of times overloaded = .................... 2920?

    I multiplied 8 by 365 to get 2920; is this assumption correct , or am I missing something? thanks for any help.
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  2. #2
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    Quote Originally Posted by skorpiox View Post
    I just need help with the last question because I'm not sure how to do it!!!

    The population of weights for men attending a local health club is normally distributed with a mean of 176-lbs and a standard deviation of 29-lbs. An elevator in the health club is limited to 32 occupants, but it will be overloaded if the total weight is in excess of 5984-lbs.
    Assume that there are 32 men in the elevator. What is the average weight beyond which the elevator would be considered overloaded?
    average weight = 187 lbs
    What is the probability that one randomly selected male health club member will exceed this weight?
    P(one man exceeds) = .3522
    If we assume that 32 male occupants in the elevator are the result of a random selection, find the probability that the elevator will be overloaded?
    P(elevator overloaded) = .0159
    If the evelator is full (on average) 8 times a day, how many times will the evelator be overloaded in one (non-leap) year?
    number of times overloaded = .................... 2920?

    I multiplied 8 by 365 to get 2920; is this assumption correct , or am I missing something? thanks for any help.
    It's impossible to know how many times the elevator will be overloaded. The question probably wants you to find the expected number of times .... In which case the answer is (2920)(0.0159) = 47 (rounded UP to the nearest whole number)
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