1. ## Check my probability answer?

Question:
The table gives the classification of all the employees of a company by gender and college degree.If one of these employees is selected at random for a member ship on the employee management committee ,determine the following.

a)P(F intersection G)
(Table)

Female-------3---------7--------------10
male----------6--------14--------------20
----------------9---------21-------------30

Attempt:
10/30I*3/30=1/30

Am I correct?
Thank you

2. There are three female graduates out of thirty employees.

3. Originally Posted by Plato
There are three female graduates out of thirty employees.
Since they are joint probability we have to use the multiplication rule:
P(F intersection G)=P(F) * P(G/F)

P(F) = 10/30
P(G/F)=3/30
10/30 * 3/30 =1/30

4. You are asked to find $\displaystyle P(G \cap F)$.
But that is $\displaystyle P(G \cap F)=P(G|F)P(F)=\left(\frac{3}{10}\right)\left(\frac {10}{30}\right)=\left(\frac{3}{30}\right)$.

But also $\displaystyle P(F \cap G)=P(F|G)P(G)=\left(\frac{3}{9}\right)\left(\frac{ 9}{30}\right)=\left(\frac{3}{30}\right)$.

5. if $\displaystyle P(M \cap G)$ was asked then

$\displaystyle P(G) * P(m/g)$

$\displaystyle 9/30 * 6/9 =1/5$

Am i correct?

6. Yes it is correct.
Out of thirty, how many male graduates are there?
Simply look at the table. It is quite clear.