Suppose that 48% of people own dogs. If you pick two people at random, what is the probability that they both own a dog? I don't know how to approach this problem properly . Any suggestion would be appreciated!
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Originally Posted by skorpiox Suppose that 48% of people own dogs. If you pick two people at random, what is the probability that they both own a dog? I don't know how to approach this problem properly . Any suggestion would be appreciated! Assuming independence, (0.48)(0.48). (I've also assumed that the two people have not been selected at random from a dog show ....)
just for curiosity, what would be the probability that at least one of them has a dog?
Originally Posted by skorpiox just for curiosity, what would be the probability that at least one of them has a dog? Pr(at least one) = 1 - Pr(none) = 1 - (0.52)^2
thanks for your time Mr. fantastic
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