Results 1 to 8 of 8

Math Help - Mean and Median

  1. #1
    Newbie
    Joined
    Jul 2009
    Posts
    8

    Mean and Median

    Hello

    This looks a really easy question but i dont actually know the answer. Could someone please tell me how i work it out

    The five number summary for the weights (in pounds) of fish caught in a bass tournament is:

    Min: 2.3
    Q1: 2.8
    Medium: 3.0
    Q3: 3.3
    Max: 4.5

    Would you expect the mean weight of all the fish caught to be higher or lower than the median? Explain

    Thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Apr 2005
    Posts
    16,453
    Thanks
    1868
    Quote Originally Posted by Stem01 View Post
    Hello

    This looks a really easy question but i dont actually know the answer. Could someone please tell me how i work it out

    The five number summary for the weights (in pounds) of fish caught in a bass tournament is:

    Min: 2.3
    Q1: 2.8
    Medium: 3.0
    Q3: 3.3
    Max: 4.5

    Would you expect the mean weight of all the fish caught to be higher or lower than the median? Explain

    Thanks
    Do you understand what "mean" and "median" are? The mean is what you might know as "arithmetic average": add all the weights together, then divide by the number of fish. The median is just the middle number, disregarding how far apart the numbers might be. I notice that the distance from the minimum weight to the middle weight is 3.0-2.3= .7 pounds while the distance from the middle weight to the maximum weight is 4.5-3.0= 1.5 pounds, twice the previous distance. So the weights tend to be "stretched" toward the high side. Remember what I said about the median disregarding things like that?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jul 2009
    Posts
    8
    2.3
    2.8
    3.0
    3.3
    4.5

    =15.9

    So 15.9/5 = 3.18 which is above the mean, so it means that it is above the median?
    Last edited by Stem01; July 20th 2009 at 09:30 AM.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor

    Joined
    Apr 2005
    Posts
    16,453
    Thanks
    1868
    I have no idea what that calculation is suppose to represent. You say it is "above the mean". Do you know what the mean is? How did you find it?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by Stem01 View Post
    2.3
    2.8
    3.0
    3.3
    4.5

    =15.9

    So 15.9/5 = 3.18 which is above the mean, so it means that it is above the median?
    The mean is NOT calculated by adding up the numbers from the five number summary and dividing by 5!! It's impossible to calculate the mean from the given information. The best that can be done is what the question is asking you to do. Please review post #2.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Junior Member
    Joined
    Aug 2008
    Posts
    38
    Quote Originally Posted by Stem01 View Post
    Hello

    This looks a really easy question but i dont actually know the answer. Could someone please tell me how i work it out

    The five number summary for the weights (in pounds) of fish caught in a bass tournament is:

    Min: 2.3
    Q1: 2.8
    Medium: 3.0
    Q3: 3.3
    Max: 4.5

    Would you expect the mean weight of all the fish caught to be higher or lower than the median? Explain

    Thanks
    MEDIAN:The Median may be defined as that value which divides a distribution into two parts such that an exactly equal number of scores fall above and below the point.
    In other words 50 percent of the scores will be above the median and the remaining 50 percent below it.
    finding the mean value for the above data given as follows:
    Here I am calculating the mean by Calculating the mean from frequency distribution.
    Class interval :1-3 ;Mid Value(x):2 Frequency(f):4(2.3,2.8,3.0,3.3);fx=8
    Class interval:4-6 ; Mid value(x):5 :
    Frequency(f):1(4.5);fx=5
    fx = 8+5=13
    Frequency(f)=4+1=5
    Mean value=summation fx /summation f = 13/5 = 2.6
    and the median for this data 2.3,2.8,3,3.3,4.5=3
    Therefore, here the mean is less than the median.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Super Member
    Joined
    Jan 2009
    Posts
    591
    Quote Originally Posted by Stem01 View Post
    Hello

    This looks a really easy question but i dont actually know the answer. Could someone please tell me how i work it out

    The five number summary for the weights (in pounds) of fish caught in a bass tournament is:

    Min: 2.3
    Q1: 2.8
    Medium: 3.0
    Q3: 3.3
    Max: 4.5

    Would you expect the mean weight of all the fish caught to be higher or lower than the median? Explain

    Thanks
    What are Q1 and Q3?
    At first I thought they were quartiles.
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by saranya View Post
    MEDIAN:The Median may be defined as that value which divides a distribution into two parts such that an exactly equal number of scores fall above and below the point.
    In other words 50 percent of the scores will be above the median and the remaining 50 percent below it.
    finding the mean value for the above data given as follows:
    Here I am calculating the mean by Calculating the mean from frequency distribution.
    Class interval :1-3 ;Mid Value(x):2 Frequency(f):4(2.3,2.8,3.0,3.3);fx=8
    Class interval:4-6 ; Mid value(x):5 :
    Frequency(f):1(4.5);fx=5
    fx = 8+5=13
    Frequency(f)=4+1=5
    Mean value=summation fx /summation f = 13/5 = 2.6
    and the median for this data 2.3,2.8,3,3.3,4.5=3
    Therefore, here the mean is less than the median.
    Sorry, but what you've posted makes no sense. It's clearly stated that the data is a five number summary. Q1 etc. are quartiles. They are not the weights of the fish in the sample.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Mean and median.
    Posted in the Statistics Forum
    Replies: 1
    Last Post: September 29th 2011, 10:07 PM
  2. Median help
    Posted in the Statistics Forum
    Replies: 6
    Last Post: January 10th 2011, 12:54 PM
  3. Mean and median.
    Posted in the Statistics Forum
    Replies: 2
    Last Post: August 23rd 2010, 06:04 PM
  4. The Median
    Posted in the Statistics Forum
    Replies: 1
    Last Post: December 4th 2009, 01:21 PM
  5. What does the median tell us?
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: April 15th 2008, 09:56 AM

Search Tags


/mathhelpforum @mathhelpforum