This problem deals with probability, and I am having trouble contemplating and establishing what is I need to do for this problem...
A box contains eight balls numbered 1 to 8. A ball is selected and the replaced. A second ball is drawn. What is the probability of drawing the number 2 first and then the number 7?
The chance of drawing a number 2 the first time is 1/8 right?
And isn't the chance to draw a number 7 after that equally 1/8? However I know this is far from the right answer, can someone explain to me what I did wrong and walk me through the necessary steps or at least an explanation of the formula to use and why?