I did:Samuel has 2 choices of travel routes. The travel time for both routes are normally distributed. The travel time for Route A has a mean of 28 min, and std deviation of 5 min, whereas Route B has a mean of 30 min and std deviation of 2 min.
If Samuel and his brother start at 7.00 am, where Samuel takes Route A while his brother takes Route B. They have to reach before7.30 am. Find who has a higher probability of reaching earlier.
P(X<30), and my answer was Samuel has a higher prob. then his brother. However the answer given is Samuel's brother. Any help would be appreciated. TIA.