Probability: Independent events

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June 28th 2009, 12:10 PM
Y-rag

Request the following if possible,
Suppose that A and B are independent events such that http://www.aleks.com/alekscgi/x/math...23%3E%233%2D03 and http://www.aleks.com/alekscgi/x/math...23%3E%233%2D53 .
Find http://www.aleks.com/alekscgi/x/math...25%60bs%23A%2A and http://www.aleks.com/alekscgi/x/math...25%60vs%23A%2A .

Would the answer to the above be:
#1. 0.12
#2. 0.58

Thank you for any help.
June 28th 2009, 03:20 PM
Plato

$\begin{gathered}<br /> P(B) = 1 - P\left( {\overline B } \right) \hfill \\<br /> P\left( {A \cap B} \right) = P(A)P(B) \hfill \\<br /> P\left( {A \cup B} \right) = P(A) + P(B) - P(A)P(B) \hfill \\ <br /> \end{gathered}$
June 29th 2009, 04:13 AM
Y-rag

Thanks Plato. That is the answer I put down. What originally threw me was the line over the B. Common sense took over and what you sent is what I had put down. Still, I was unsure until your confirmation. Appreciate the help.

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