A="Both balls are blue"
B="Both balls are green"
I calculated the probability that a book was torn, and took 1 minus that probability.
3) Since the coin is fair, it is a 50-50 shot that either of them will go first. But given the probabilites here it doesnt matter who goes first, it is always 50-50 for a draw. So...
A="The bus is not late"
B="It does not rain"
Then by Bayes Theorem:
Here we calculated "Given that the bus was not late, what is the probability of it not raining". So therefore we must take to get the probability of it raining.
I hope these are right, Iīm confident mrFantastic or anyone more experienced will soon give their input as well.