you don't use this number again, so there are (49-1)=48 balls left
2. draw: you draw one number out of 48 => 48 possibilities for that
You do not use that number again, so there are 47 numbers left
3. draw: you draw one out of 47 (47 possibilities)
4. draw: one out of 46
5. draw: one out of 45
6. draw: one out of 44
So there are 49*48*47*46*45*44 different ways of drawing 6 numbers out of 49.
Edit: I made a mistake. Sorry
Plato gave the right answer: Because of
you need to divide by 6!, thusA lottery ticket is treated as a combination not a permutation, order makes no difference.
is the solution!