Results 1 to 4 of 4

Math Help - Counting and Probability Help

  1. #1
    Newbie
    Joined
    Mar 2009
    Posts
    4

    Counting and Probability Help

    okay so I have a test tomorrow and I was doing the review questions. I am stock on 3 of the questions. It be greatly appreciated if you guys can help. Here are the questions:


    1. in a bag of candy canes, there are 14 broken candies, mixed in with 20 good ones. if neha chooses 3 candies at random from the bag what is the probability that all 3 are good

    2. Think of a word in the English language in which the probability of selecting a vowel is 3/5.

    3. In how many ways can a group of five people be chosen from seven couples (each of which has one more and one female) to form a club, given each of the following conditions?
    A) All are equally eligible for the club
    B) The club must include two females and 3 males.
    Thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member apcalculus's Avatar
    Joined
    Apr 2009
    From
    Boston
    Posts
    293
    Quote Originally Posted by ajmaal14 View Post
    okay so I have a test tomorrow and I was doing the review questions. I am stock on 3 of the questions. It be greatly appreciated if you guys can help. Here are the questions:


    1. in a bag of candy canes, there are 14 broken candies, mixed in with 20 good ones. if neha chooses 3 candies at random from the bag what is the probability that all 3 are good

    2. Think of a word in the English language in which the probability of selecting a vowel is 3/5.

    3. In how many ways can a group of five people be chosen from seven couples (each of which has one more and one female) to form a club, given each of the following conditions?
    A) All are equally eligible for the club
    B) The club must include two females and 3 males.
    Thanks
    Some help with the first two:

    1)
    P(first one is good) = 20/34
    P(second one is good) = 19/33
    P(third one is good) = 18/32

    Multiply all three probabilities since the events are independent.

    2) route
    above

    Good luck!!
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Nov 2006
    From
    Florida
    Posts
    228
    1)
    There are a total of 34 candies in the bag. The probability that the first is good is 20/34. Thus leaving 33, so the probability the second is good is now 19/33. By similar logic the probability for the third being good is 18/32. Thus the final answer is \frac{20\cdot 19\cdot 18}{34\cdot 33\cdot 32}
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Mar 2009
    Posts
    4

    Thanks a lot just dont get the multiplying part

    Thanks a lot man
    k soo do 20/34 x 19/33 x 18/32
    if i do that i get 285/1496
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Probability Counting Rules
    Posted in the Advanced Statistics Forum
    Replies: 3
    Last Post: October 1st 2011, 08:35 PM
  2. Probability counting excercise
    Posted in the Statistics Forum
    Replies: 4
    Last Post: March 8th 2011, 07:49 PM
  3. Probability and counting problems
    Posted in the Statistics Forum
    Replies: 4
    Last Post: April 22nd 2008, 06:03 AM
  4. Counting & Probability help
    Posted in the Discrete Math Forum
    Replies: 2
    Last Post: April 13th 2008, 03:38 PM
  5. Help with probability and counting problems
    Posted in the Advanced Statistics Forum
    Replies: 9
    Last Post: October 9th 2007, 07:13 AM

Search Tags


/mathhelpforum @mathhelpforum