Calculate the probability of tossing exactly 2 heads in 5 coin tosses
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Originally Posted by shelleeblue Calculate the probability of tossing exactly 2 heads in 5 coin tosses Binomial probability problem. Probability of success (a head) on a single toss is p=0.5. The probability of exactly n success in N trials is: P(n,N)=N!/[n! (N-n)!] p^n (1-p)^(N-n) so in this case: P(2,5)=5!/[2! 3!] 0.5^5 = 0.3125 RonL
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