Hello, Jhonson!

Here's an "eyeball" solution . . .A family with 5 children is selected at random.

What is the probability that the family has at least 3 boys?

Of all the possible combinations of gender among five children,

. . exactly HALF of them have more boys than girls.

. . (And the other half has more girls than boys.)

Therefore: .

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A more "mathematical" solution . . .

There are: . possible sets of gender.

How many have 3 boys and 2 girls?. .

How many have 4 boys and 1 girl?. .

How many have 5 boys?. .

Hence, there are: . cases with 3 or more boys.

Therefore: .