Originally Posted by

**Kasper** For this question, I tried it using $\displaystyle P(x success)=_{n}C_{k}P^k(1-P)^{n-k}$, but It doesn't feel right. and I'm not getting the correct answer, I think I just need a push in the right direction on this one.

Am I supposed to set $\displaystyle P(xsuccess)=0.2508$ and solve backwards? I tried plugging $\displaystyle 0.2508$ as P in the above formula and solving, but that was more of a wild shot.

I'm not sure where to go with this one. =/ Any help would be appreciated!