1. probability ?

what are the odds in favour of each events?

a) getting a number greater than 1 when a number cube labelled 1 to 6 is rolled

2. Originally Posted by hscott4
what are the odds in favour of each events?

a) getting a number greater than 1 when a number cube labelled 1 to 6 is rolled
Number of different outcomes is 6.

The amount of values that are greater than 1, 5 (2, 3,...6)

Therefore the probability is 5 out of 6 or $\frac{5}{6}$, assuming the dice/number cube is fair.

3. Originally Posted by hscott4
what are the odds in favour of each events?

a) getting a number greater than 1 when a number cube labelled 1 to 6 is rolled
Pr(X > 1) = 5/6.

Now read this: Odds - Wikipedia, the free encyclopedia

4. thank you very much, but could you make it step by step so I understand it please??

2) Getting a 2 when a card is randomly picked from a deck of playing cards.

3) Getting the sum 5 when two number cubes labelled 1 to 6 are rolled and the numbers are added.

5. 2. n/N =4/52=1/13
Number of favourable events divided by total number of events.

3. same here... n/N=4/36=1/9
There are 6 times 6 total out comes, but you want just the four...
(1,4), (2,3), (3,2), (4,1), where the pairs represent the two dice.

6. Hello, hscott4!

Do you mean "odds" . . . or "probability"?
They are two different concepts.

What are the odds in favour of:

a) getting a number greater than 1 when a number cube labelled 1 to 6 is rolled.

There are six possible outcomes: . $\{1,2,3,4,5,6\}$ . . . all equally likely.

There are five outcomes greater than 1: . $\{2,3,4,5,6\}$

The probability of a number greater than 1 is: . ${\color{blue}\frac{5}{6}}$

The odds in favor of a number greater than 1 is . ${\color{blue}5:1}$