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Math Help - [SOLVED] Find the probability. (Is my answer correct)

  1. #1
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    [SOLVED] Find the probability. (Is my answer correct)

    A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. Find the probability that you have all orange candies. Find the probability that you have all orange candies.

    I got 0.00606061 which is the decimal fo 6/990.

    I did it by multiplying 3*2*1=6
    And then 11*10*9=990

    And then I divided 6 by 990 which gave me that decimal .. Rounded it off to 0.0061

    Is this correct? Or is there something wrong in my process.

    Thanks.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by hellotarina View Post
    A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. Find the probability that you have all orange candies. Find the probability that you have all orange candies.

    I got 0.00606061 which is the decimal fo 6/990.

    I did it by multiplying 3*2*1=6
    And then 11*10*9=990

    And then I divided 6 by 990 which gave me that decimal .. Rounded it off to 0.0061

    Is this correct? Or is there something wrong in my process.

    Thanks.
    looks fine. i suppose you understand why you did what you did, so i won't go into that
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  3. #3
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    LOL. Thanks. I sometimes make something easy seem difficult... but what matters is that I get the process... right
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  4. #4
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    Quote Originally Posted by hellotarina View Post
    A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. Find the probability that you have all orange candies. Find the probability that you have all orange candies.
    I think the result is 1/11P3 = 1/165.
    one way to take 3 pieces of orange candies; and 11P3 ways to take 3 pieces of candy.
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mahefo View Post
    i think the result is 1/11p3 = 1/165.
    One way to take 3 pieces of orange candies; and 11p3 ways to take 3 pieces of candy.
    6/990 = 1/165
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  6. #6
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    Quote Originally Posted by mahefo View Post
    I think the result is 1/11P3 = 1/165.
    one way to take 3 pieces of orange candies; and 11P3 ways to take 3 pieces of candy.
    I think that is \frac{6}{990} simplified. Whichever way you did it seems easier than my way. Lol. If you can explain the shorter way... you're welcome to.
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