apparently, according to a paper mark scheme

$\displaystyle

f(y) = \left\{ \begin{array}{l l}

\frac{1}{9} (2y^{3} + y), & 1 \leq y \leq 2 \\

& \\

0 & \text{otherwise} \end{array} \right.

$

Anyway im interested in $\displaystyle \frac{1}{9}(2y^{3}+y)$

is a valid probability density function

But if you put the upper limit 2 in you get 2 out, when probability ranges between 0 and 1.

Thanks