Results 1 to 5 of 5

Math Help - Number of outcomes of two dice, three throws

  1. #1
    Newbie
    Joined
    May 2009
    Posts
    3

    Number of outcomes of two dice, three throws

    What is the maximum number of outcomes of a pair of dice thrown three times? For example:

    1st Set: 2, 10, 4
    2nd Set: 2, 2, 2
    3rd Set: 10, 4, 2

    Is there a universal formula I can use to calculate this problem with different variables? (For example, pair of dice thrown five times, three dice thrown six times, etc.)

    Any help would be appreciated!
    Last edited by seavari; May 25th 2009 at 03:06 PM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,380
    Thanks
    1473
    Awards
    1
    Quote Originally Posted by seavari View Post
    What is the maximum number of outcomes of a pair of dice thrown three times? For example:
    1st Set: 2, 10, 4
    2nd Set: 2, 2, 2
    3rd Set: 10, 4, 2
    Is there a universal formula I can use to calculate this problem with different variables? (For example, pair of dice thrown five times, three dice thrown six times, etc.)
    It is not at all clear as to what your question means.
    If we toss a pair of dice, then add the showing numbers we have eleven outcomes: 2 to 12.
    If we repeat this three times, we get a set of ordered triples.
    There are then 11^3 possible triples.

    Is that the meaning of this question?
    If not please try to explain further.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    May 2009
    Posts
    3
    Quote Originally Posted by Plato View Post
    It is not at all clear as to what your question means.
    If we toss a pair of dice, then add the showing numbers we have eleven outcomes: 2 to 12.
    If we repeat this three times, we get a set of ordered triples.
    There are then 11^3 possible triples.

    Is that the meaning of this question?
    If not please try to explain further.
    (I'm sorry, it's been a really long time since I last tried to grapple a math problem. ^^; )

    I think you answered my question though...so there could be 1,331 possible outcomes? (For example, "2, 3, 4" being one possible outcome.)

    If I repeated four times instead of three, it would be 11^4?

    If I used just one die and cast three times, would it be 6^3?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,380
    Thanks
    1473
    Awards
    1
    Quote Originally Posted by seavari View Post
    I think you answered my question though...so there could be 1,331 possible outcomes? (For example, "2, 3, 4" being one possible outcome.)
    If I repeated four times instead of three, it would be 11^4?
    If I used just one die and cast three times, would it be 6^3?
    Yes that is correct.
    If repeated N times instead of three, it would be 11^N?
    If just one die and cast N times, would it be 6^N?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    May 2009
    Posts
    3
    You have made my day! Thank you so much! I didn't know it would be so simple...you are a hero!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. number of throws till die shows all faces
    Posted in the Statistics Forum
    Replies: 1
    Last Post: August 10th 2011, 02:35 AM
  2. Number of possible outcomes.
    Posted in the Advanced Statistics Forum
    Replies: 4
    Last Post: October 11th 2010, 03:38 PM
  3. Replies: 2
    Last Post: May 9th 2010, 10:08 AM
  4. Probability for dice roll outcomes
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: September 8th 2009, 07:35 AM
  5. 180 throws with a normal dice
    Posted in the Statistics Forum
    Replies: 2
    Last Post: August 7th 2009, 08:22 AM

Search Tags


/mathhelpforum @mathhelpforum