a deck has 52 cards, 12 face cards and 4 aces are removed, from these 16 cards 4 are chosen, how many combinations are possible that have at least 2 black cards.
The answer is 1302
I get 154?
What I did was,
there are 8 black cards so,
8c2+8c3+8c4=154
I could swear I did this right.
Hello, brentwoodbc!
You're forgetting about the red cards . . .
A deck has 52 cards.
12 face cards and 4 aces are removed.
From these 16 cards, 4 are chosen.
How many combinations are possible that have at least 2 black cards?
The answer is 1302.
To get "at least 2 Blacks", we want: .(2 Black, 2 Red) or (3 Black, 1 Red) or (4 Black).
. . There are: .ways to get 2 Black, 2 Red.
. . There are: .ways to get 3 Black, 1 Red.
. . There are: .ways to get 4 Black.
Therefore, there are: .ways to get at least 2 Blacks.
Ya I know thank you.Originally Posted by Soroban
Hello, brentwoodbc!
You're forgetting about the red cards . . .
To get "at least 2 Blacks", we want: .(2 Black, 2 Red) or (3 Black, 1 Red) or (4 Black).
. . There are: .
. . There are: .
. . There are: .
Therefore, there are: .
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