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Math Help - simple probability

  1. #1
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    simple probability

    Hi everyone,

    Im trying to brush up on some maths, and looking at probabilities.

    For the life of me I cant work this relatively simple question I set my self up with.

    Player 1 has a six sided dice, with each side numbered 1 to 6
    Player 2 has a four sided dice, with each side numbered 1 to 4

    Each player throws their dice once.

    I am trying to work out the probability that player 2 will throw the highest value.

    My attempt is 0.33, but looking for some validation.

    Thanks
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  2. #2
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    There are a total number of 24 possible rolls for the two die, and p2 only throws a higher number 6 times

    P1 P2
    1 1
    1 2 \leftarrow
    1 3 \leftarrow
    1 4 \leftarrow
    2 1
    2 2
    2 3 \leftarrow
    2 4 \leftarrow
    3 1
    3 2
    3 3
    3 4 \leftarrow
    4
    4
    4
    4
    5
    5
    5
    5
    6
    6
    6
    6
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  3. #3
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    Quote Originally Posted by unigee View Post
    Player 1 has a six sided dice, with each side numbered 1 to 6
    Player 2 has a four sided dice, with each side numbered 1 to 4
    Each player throws their dice once.
    I am trying to work out the probability that player 2 will throw the highest value.
    The word ‘dice’ is the plural of the word ‘die’.
    So each player throws his die.

    The probability that player 2 will throw the highest value acts like this.
    P(x=k) is the probability that player 2 has k as the highest value.
    P(x=1)=0
    P(x=2)=\left(\frac{1}{4}\right)\left(\frac{1}{6}\r  ight)
    P(x=3)=\left(\frac{1}{4}\right)\left(\frac{2}{6}\r  ight)
    P(x=4)=\left(\frac{1}{4}\right)\left(\frac{3}{6}\r  ight)
    Add them up.
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