I guess its because if you have
012 it could be 012,021,120,102,201,210? 3!.... I guess thats the easiest way?
in a pick three lottery 3 digits are randomly chosen from 0-9,
The three numbers can be the same.
what are the odds getting the 3 numbers right?
what are the odds of getting them in the correct order?
The order one I got right, 10x10x10=1000
but the other one I cannot get....the answer is 1/167 but I dont see how that is found.
Take your example. Suppose that the winning draw is 012.
If I had bought the ticket 010 then do I win? All my numbers are in the ticket.
Suppose the wining draw is 343.
I buy the ticket 345. Do I win?
What does a winning ticket actually mean?
Oh I get what you mean like if 012 was drawn and you picked 111 hmm. I see what you mean, I think it means to pick all of the numbers drawn either in order or not.
I just looked in the book again and the question is about 100 words long so I shortened it, if you look at it that way even the books question is questionable.
the answer to the second question is 1 in 167 is worked out as follows
there are 10 * 10 * 10 = 1000
say if you picked the 3 numbers , 123
and 321 came out , would you lose because the order was wrong?
if you had to get the right order your odds of winning are 1 in 1000
if 123 , 321 , 132 , 312 , 213 , 231 are treated as the same ,,meaning
any one of them would be a winner like in the lottery , you need to eliminate them from the 1000
10 * 10 * 10 = 1000 divided by 3 * 2 * 1 , ie 6 = 167
so your chances of winning are now 1 in 167
now 123 , 321 , 132 , 312 , 213 , 231
are treated as the same
so any 1 of the in any order is a winner! yippy
i hope this helps