[note...n choose k entails the following: n!/(k!(n-k)!)

i have to simplify following statement but don't know how to go about it:

(n choose 4) + 2(n choose 5) + (n choose 6)

so if anyone could help me, that would be great :)

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- Dec 16th 2006, 12:52 PMbuckaroobillcombinations
[note...n choose k entails the following: n!/(k!(n-k)!)

i have to simplify following statement but don't know how to go about it:

(n choose 4) + 2(n choose 5) + (n choose 6)

so if anyone could help me, that would be great :) - Dec 16th 2006, 01:39 PMThePerfectHacker
- Dec 16th 2006, 03:10 PMSoroban
Hello, buckaroobill!

My approach is slightly different . . .

Quote:

Simplify: .

We have: .

. .

Factor: .

Common denominator: .

. .

. .

. .