permutations question #2
I thought I had this question solved and I sort of did bu I got only half of the answer.
so what I did was
6!/720=(6-n)! ****Also why cant you cancel the ! here, I mean why cant you divide it out here?
but the answer that is given is 5 or 6? where is this 6 coming from?
You can't divide it out there because the factorial is an operation, not a variable. You got to , and then found that 6!=720, right? So then . You got the case for 1!=1, so that n=5 is a solution, as (6-5)!=1!=1. But there is another solution, as you noted. Here is a hint: what is 0! ("zero factorial")?
0!=1 but I dont see how that is applied to this question, and if its an operation not a variable why can you cancel it later.
and what I mean by canceling later is my teacher said to do this
10!=90(10-n)! *****I want to know why you cant cancel here.
8!=(10-n)!****but you can cancel here
but if you canceled at 10!=90(10-n)! you have n= -.888888
I dont see why my first example has 2 solutions and my second has one.
Because you had (6-n)!=1. 1!=1, and as you noted, 0!=1, which means that 6-n can be 1 or 0, and thus n=5 or 6.
ya thanks I thought about it and also 7*6*5*4*3*2 when you cancel is =1!, =7*6*5*2*1 when you cancel its = 0! then when you cancel the factorials your left with 1/0. thanks.
Originally Posted by TwistedOne151