Hello,
Hmm I'll give it some thought...
I think the main idea for this is :
, and where is the score of the n-th dice.
But I haven't tried to use it for a formal proof yet.
A die is rolled 1000 times. Show that the probability that the sum of the numbers shown is 1100 is the same as the probability that the sum of the numbers shown is 5900.
Not really sure how to go about doing this.
Some hints would be nice.
I would appreciate it if I wasn't given the answer all written out. I just want an idea of where to start.
thank you in advance