Three coins are tossed. Find the probabilikty that they all land heads up for each known condition.
6. The first coin shows a head.
My work: 2*2*2=8 possibilities
8 Pr 2=56 ways to choose that so it fits that one shows a head..
7. At least one coin shows a head.
8. At least two coins show heads
...that's all I know how to work out so far.
Also, if somebody could explain how this logically makes sense, I'd really appreciate it! (Something like a tangible example or whatnot would be great)