Hi,
I have the following question to answer:
"Three fair dice are rolled. What is the probability of at least one of the dice coming up a four, five or a six?"
I calculated it the following way:
P(not 4 or 5 or 6 coming up on 1 dice) = 3/6 = 1/2
for 3 dice = 1/2 * 1/2 * 1/2 = 1/8
P(4 or 5 or 6 coming up on any of 3 dice) = 1 - P(not 4 or 5 or 6 on any of 3 dice) = 1 - 1/8 = 7/8
Is this approach correct?
Can this also be calculated with the binomial distribution? Could you please give a solution to that?
Thanks.