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Math Help - Easy Question

  1. #1
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    Easy Question

    A group of 80 females consists of 54 dancers and 35 singers. Each member of the group is either a dancer or a singer or both. The probability that a randomly selected member of the group is a singer given that she is a dancer is how much?


    Please show complete working out.


    Any help on the above will be appreciated.
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  2. #2
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    Hello, Joker37!

    A group of 80 females consists of 54 dancers and 35 singers.
    Each member of the group is either a dancer or a singer or both.
    Find the probability that a randomly selected member of the group
    is a singer, given that she is a dancer.
    Organize the data in a chart.

    . . \begin{array}{c||c|c||c}<br />
& \text{Dancers} & \sim\text{Dance} & \text{Total}\\ \hline \hline<br />
\text{Singers} & 9 & 26 & 35 \\ \hline<br />
\sim\text{Sing} & 45 & 0 & 45 \\ \hline \hline<br />
\text{Total} & 54 & 26 & 80 \end{array}


    There are 54 dancers.
    Among them, 9 are also singers.

    Therefore: . P(\text{singer}|\text{dancer}) \:=\:\frac{9}{54} \;=\;\frac{1}{6}

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  3. #3
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    Quote Originally Posted by Joker37 View Post
    A group of 80 females consists of 54 dancers and 35 singers. Each member of the group is either a dancer or a singer or both. The probability that a randomly selected member of the group is a singer given that she is a dancer is how much?


    Please show complete working out.


    Any help on the above will be appreciated.
    The approach suggested at http://www.mathhelpforum.com/math-he...-one-easy.html can also be used.
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