# Probability word problem

• May 7th 2009, 04:50 PM
puzzledwithpolynomials
Probability word problem
A baseball team's pitching staff has 5 left-handed and 8 right-handed pitchers. If 2 pitchers are randomly chosen to warm up, what is the probability that at least one of them is right-handed?
(Angry)
• May 7th 2009, 07:34 PM
noob mathematician
Quote:

Originally Posted by puzzledwithpolynomials
A baseball team's pitching staff has 5 left-handed and 8 right-handed pitchers. If 2 pitchers are randomly chosen to warm up, what is the probability that at least one of them is right-handed?
(Angry)

Consider two possibilities:

$P(\textrm{one right-handed})=(\frac{8}{13})(\frac{5}{12})+(\frac{5}{13 })(\frac{8}{12})$

$P(\textrm{two right-handed})=(\frac{8}{13})(\frac{7}{12})$