Thread: Just a Binomial prob question

Ok so say p = 0.10 and there are 20 trials so n = 20

using the nCx p^x q^n-x method (bernoulli trial) how would i work out the probabiltiy of x being less than 5

so like, P(x < 5)

thanks alot

Originally Posted by I Drink and Derive

Ok so say p = 0.10 and there are 20 trials so n = 20

using the nCx p^x q^n-x method (bernoulli trial) how would i work out the probabiltiy of x being less than 5

so like, P(x < 5)

thanks alot

Caluclate Pr(X = 0) + Pr(X = 1) + Pr(X = 2) + Pr(X = 3) + Pr(X = 4).

not as complicated as i thought, thanks alot