We have 60 TV's on the shop , 5 of them have defects.
if we buy 2 TV 's how is the probability that both have defects ?
Yes, simply, prob to get 1 defective tv =5/60
Ermm my mistake, binomial distribution applies here....
Some hints there
Now if the two "we" 's in the question refer to different actors then yes the answer is different.
So the probability of both being defective will be . You can think about where the different bits of this answer come from, and I'll let you simplify it.
Alternatively, you can use the hypergeometric distribution if you know it.