43. From a group of 20 men and 16 women, 2 people are chosen at random. Find the probability of:
a) 1 man and 1 woman being chosen
b) 2 men being chosen
c) 2 women being chosen
a. 1 man being chosen = 20/36 and 1 woman being chosen is 16/36
The probability of both would be the product of the two probabilities I believe.
b. The probability of the first man being chosen is 20/36 and the probability of the second is 19/35 since you are now one man down. Multiply the two probabilities.
c. The probability of the first woman being chosen is 16/36 and the second is 15/35. Multiply the two like above.