Hello,

Good attempt, but that's... not the solution...

You should remember that the sum of probabilitiesmustbe 1. And

In order to solve that, let a be the probability for 1.

We know that 1,2,3 show up equally, that is to say with the probability a.

We know that 4 shows up twice as often as 1, that is to say with the probability 2a.

We know that 4,5,6 show up equally, that is to say with the probability 2a.

Now the sum of probabilities is :

And we know that this sum must be 1. So what is the value of a ?

Now, with these new values, you can try this 2nd question successfullyProbability an even number is rolled = 1/2 ... Odd number = 2/3b.

I'm taking a complete shot in the dark at this so any help would be appreciated. Is there any specific formula I should be using?

I see that you had the correct reasoning for finding 1/2 and 2/3.

Again, since "getting an even number" and "getting an odd number" are complementary, the sum of their probability should be 1.

Does this help ?