Results 1 to 2 of 2

Math Help - Coin problem.

  1. #1
    Junior Member
    Joined
    Mar 2009
    Posts
    52

    Coin problem.

    Hi,

    I stuck in the below question so required assistance :-

    Q - A fair coin is tossed 10 times. Find the probability that 2 heads do not occur consecutively.

    a) 1/(2^4) b) 1/(2^3) c) 1/(2^5) d) None of these.


    Any help would be greatly appreciated.

    Thanks,
    Ashish
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,964
    Thanks
    1784
    Awards
    1
    Quote Originally Posted by a69356 View Post
    Q - A fair coin is tossed 10 times. Find the probability that 2 heads do not occur consecutively.
    a) 1/(2^4) b) 1/(2^3) c) 1/(2^5) d) None of these.
    This problem takes a bit of work. There are six cases to calculate then add them up.
    You can have anywhere from zero to five heads. You cannot have six. Why.

    In the case of having three heads and seven tails, the tails separate the heads.
    So there are eight places to place the three heads: _T_T_T_T_T_T_T_.
    That means that there are {8 \choose 3} ways to do that.
    So the probability of this case is {8 \choose 3} \frac{1}{2^{10}}

    Now you have five more cases to work out.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. coin problem
    Posted in the Algebra Forum
    Replies: 3
    Last Post: May 19th 2010, 09:33 AM
  2. Coin problem
    Posted in the Statistics Forum
    Replies: 1
    Last Post: February 5th 2010, 01:07 PM
  3. Coin problem
    Posted in the Math Puzzles Forum
    Replies: 7
    Last Post: July 24th 2009, 11:07 AM
  4. Coin Problem
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: March 18th 2009, 09:44 AM
  5. Coin problem
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: January 21st 2009, 02:20 AM

Search Tags


/mathhelpforum @mathhelpforum